A car rental company charges a flat fee of $21.50 and an hourly charge of $14.50......?

This means that cost is a function of the hours the car is rented plus the flat fee.








a) Write this relationship in equation form.


b) Find the cost if the car is rented for 2.5 hours.


c) Determine how long the car was rented if the bill came to $250.


d) Determine the domain and range of the function in this context: your budget limits you to paying a maximum of $210 for the rental.A car rental company charges a flat fee of $21.50 and an hourly charge of $14.50......?
This is rather basic...





To begin, you need to take a look at what info the problem is sharing...





1.) The constant charge is 21.50... even if you rent it for 1 hour, 1day or 1 year, you pay a set 21.50.





2.) The Hourly charge is 14.50 so that is your VARIABLE H and it is the RATE of Change.





a.) The relationship would be:





$14.50h + $21.50= Price to Rent Car





b.) $14.50 (2.5) + 21.50 =


$36.25+$21.50= $57.75





c.) $14.50h + $21.50 = $250.00


$14.50h = $228.50


h =15h and 45 minutes





d.) $14.50h + $21.50 = $210.00





$14.50h = $188.50





h = 13 hrs so the range would be 0-13 hrs.A car rental company charges a flat fee of $21.50 and an hourly charge of $14.50......?
A = Cost = 21.50 + 14.50 x X


B = 21.50 + 14.50 x 2.5 = 57.75


C = 250 - 21.50 =228.50 then 228.50/14.5 = 15.75 hours


D = 210 - 21.50 = 188.50 to spend hourly, 188.50/14.5 = 13 hours
a. Let x = hours


Cost = 21.50 + 14.50 x





b. if the car is rented for 2.5 hours, so x=2.50


Cost = 21.50 + 14.50 (2.50)


= 57.75





c. cost = 250 = 21.50 + 14.50x


x = 15.7 hours





d. domain = 210 - 21.50 = 188.50


range of hours = 188.50 / 14.50 = 13 hrs